Python min() |
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The min() function returns the smallest item in an iterable. It can also be used to find the smallest item between two or more parameters. Example numbers = [9, 34, 11, -4, 27] # find the smallest number min_number = min(numbers) print(min_number) # Output: -4The min() function has two forms: # to find the smallest item in an iterable min(iterable, *iterables, key, default) # to find the smallest item between two or more objects min(arg1, arg2, *args, key) 1. min() with iterable arguments min() SyntaxHere's the syntax of the min() function min(iterable, *iterables, key, default) min() Parameters iterable - an iterable such as list, tuple, set, dictionary, etc. *iterables (optional) - any number of iterables; can be more than one key (optional) - key function where the iterables are passed and comparison is performed based on its return value default (optional) - default value if the given iterable is empty min() Return Valuemin() returns the smallest element from an iterable. Example 1: Get the smallest item in a list number = [3, 2, 8, 5, 10, 6] smallest_number = min(number); print("The smallest number is:", smallest_number)Output The smallest number is: 2If the items in an iterable are strings, the smallest item (ordered alphabetically) is returned. Example 2: The smallest string in a list languages = ["Python", "C Programming", "Java", "JavaScript"] smallest_string = min(languages); print("The smallest string is:", smallest_string)Output The smallest string is: C ProgrammingIn the case of dictionaries, min() returns the smallest key. Let's use the key parameter so that we can find the dictionary's key having the smallest value. Example 3: min() in dictionaries square = {2: 4, 3: 9, -1: 1, -2: 4} # the smallest key key1 = min(square) print("The smallest key:", key1) # -2 # the key whose value is the smallest key2 = min(square, key = lambda k: square[k]) print("The key with the smallest value:", key2) # -1 # getting the smallest value print("The smallest value:", square[key2]) # 1Output The smallest key: -2 The key with the smallest value: -1 The smallest value: 1
In the second min() function, we have passed a lambda function to the key parameter. key = lambda k: square[k]The function returns the values of dictionaries. Based on the values (rather than the dictionary's keys), the key having the minimum value is computed. Few Notes: If we pass an empty iterator, a ValueError exception is raised. To avoid this, we can pass the default parameter. If we pass more than one iterators, the smallest item from the given iterators is returned. 2. min() without iterable min() SyntaxHere's the syntax of min() function min(arg1, arg2, *args, key) min() Parameters arg1 - an object; can be numbers, strings, etc. arg2 - an object; can be numbers, strings, etc. *args (optional) - any number of objects key (optional) - key function where each argument is passed, and comparison is performed based on its return valueBasically, the min() function can find the smallest item between two or more objects. min() Return Valuemin() returns the smallest argument among the multiple arguments passed to it. Example 4: Find the minimum among the given numbers result = min(4, -5, 23, 5) print("The minimum number is:", result)Output The minimum number is -5If you need to find the largest item, you can use the Python max() function. |
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